3(x+2)=-6x+33

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Solution for 3(x+2)=-6x+33 equation: 



3(x+2)=-6x+33

We move all terms to the left:

3(x+2)-(-6x+33)=0

We multiply parentheses

3x-(-6x+33)+6=0

We get rid of parentheses

3x+6x-33+6=0

We add all the numbers together, and all the variables

9x-27=0

We move all terms containing x to the left, all other terms to the right

9x=27

x=27/9

x=3

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