3(x+2)=12+4(5x-1)

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Solution for 3(x+2)=12+4(5x-1) equation: 



3(x+2)=12+4(5x-1)

We move all terms to the left:

3(x+2)-(12+4(5x-1))=0

We multiply parentheses

3x-(12+4(5x-1))+6=0



We calculate terms in parentheses: -(12+4(5x-1)), so:

12+4(5x-1)

determiningTheFunctionDomain
4(5x-1)+12

We multiply parentheses

20x-4+12

We add all the numbers together, and all the variables

20x+8

Back to the equation:

-(20x+8)



We get rid of parentheses

3x-20x-8+6=0

We add all the numbers together, and all the variables

-17x-2=0

We move all terms containing x to the left, all other terms to the right

-17x=2

x=2/-17

x=-2/17

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