3(x+2)=12-2(x-2)

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Solution for 3(x+2)=12-2(x-2) equation: 



3(x+2)=12-2(x-2)

We move all terms to the left:

3(x+2)-(12-2(x-2))=0

We multiply parentheses

3x-(12-2(x-2))+6=0



We calculate terms in parentheses: -(12-2(x-2)), so:

12-2(x-2)

determiningTheFunctionDomain
-2(x-2)+12

We multiply parentheses

-2x+4+12

We add all the numbers together, and all the variables

-2x+16

Back to the equation:

-(-2x+16)



We get rid of parentheses

3x+2x-16+6=0

We add all the numbers together, and all the variables

5x-10=0

We move all terms containing x to the left, all other terms to the right

5x=10

x=10/5

x=2

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