3(x+2)=2(10-x)=11

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Solution for 3(x+2)=2(10-x)=11 equation: 



3(x+2)=2(10-x)=11

We move all terms to the left:

3(x+2)-(2(10-x))=0

We add all the numbers together, and all the variables

3(x+2)-(2(-1x+10))=0

We multiply parentheses

3x-(2(-1x+10))+6=0



We calculate terms in parentheses: -(2(-1x+10)), so:

2(-1x+10)

We multiply parentheses

-2x+20

Back to the equation:

-(-2x+20)



We get rid of parentheses

3x+2x-20+6=0

We add all the numbers together, and all the variables

5x-14=0

We move all terms containing x to the left, all other terms to the right

5x=14

x=14/5

x=2+4/5

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