3(x+2)=2(2x+3)

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Solution for 3(x+2)=2(2x+3) equation: 



3(x+2)=2(2x+3)

We move all terms to the left:

3(x+2)-(2(2x+3))=0

We multiply parentheses

3x-(2(2x+3))+6=0



We calculate terms in parentheses: -(2(2x+3)), so:

2(2x+3)

We multiply parentheses

4x+6

Back to the equation:

-(4x+6)



We get rid of parentheses

3x-4x-6+6=0

We add all the numbers together, and all the variables

-x=0

x=0/-1

x=0

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