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3(x+2)=2(2x-6)
We move all terms to the left:
3(x+2)-(2(2x-6))=0
We multiply parentheses
3x-(2(2x-6))+6=0
We calculate terms in parentheses: -(2(2x-6)), so:We get rid of parentheses
2(2x-6)
We multiply parentheses
4x-12
Back to the equation:
-(4x-12)
3x-4x+12+6=0
We add all the numbers together, and all the variables
-1x+18=0
We move all terms containing x to the left, all other terms to the right
-x=-18
x=-18/-1
x=+18
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