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3(x+2)=2(5x+1)
We move all terms to the left:
3(x+2)-(2(5x+1))=0
We multiply parentheses
3x-(2(5x+1))+6=0
We calculate terms in parentheses: -(2(5x+1)), so:We get rid of parentheses
2(5x+1)
We multiply parentheses
10x+2
Back to the equation:
-(10x+2)
3x-10x-2+6=0
We add all the numbers together, and all the variables
-7x+4=0
We move all terms containing x to the left, all other terms to the right
-7x=-4
x=-4/-7
x=4/7
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