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3(x+2)=2(x+2)+2
We move all terms to the left:
3(x+2)-(2(x+2)+2)=0
We multiply parentheses
3x-(2(x+2)+2)+6=0
We calculate terms in parentheses: -(2(x+2)+2), so:We get rid of parentheses
2(x+2)+2
We multiply parentheses
2x+4+2
We add all the numbers together, and all the variables
2x+6
Back to the equation:
-(2x+6)
3x-2x-6+6=0
We add all the numbers together, and all the variables
x=0
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