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3(x+2)=2(x+5)-9
We move all terms to the left:
3(x+2)-(2(x+5)-9)=0
We multiply parentheses
3x-(2(x+5)-9)+6=0
We calculate terms in parentheses: -(2(x+5)-9), so:We get rid of parentheses
2(x+5)-9
We multiply parentheses
2x+10-9
We add all the numbers together, and all the variables
2x+1
Back to the equation:
-(2x+1)
3x-2x-1+6=0
We add all the numbers together, and all the variables
x+5=0
We move all terms containing x to the left, all other terms to the right
x=-5
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