3(x+2)=2(x-1)+3

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Solution for 3(x+2)=2(x-1)+3 equation: 



3(x+2)=2(x-1)+3

We move all terms to the left:

3(x+2)-(2(x-1)+3)=0

We multiply parentheses

3x-(2(x-1)+3)+6=0



We calculate terms in parentheses: -(2(x-1)+3), so:

2(x-1)+3

We multiply parentheses

2x-2+3

We add all the numbers together, and all the variables

2x+1

Back to the equation:

-(2x+1)



We get rid of parentheses

3x-2x-1+6=0

We add all the numbers together, and all the variables

x+5=0

We move all terms containing x to the left, all other terms to the right

x=-5

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