3(x+2)=2-(x+4)

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Solution for 3(x+2)=2-(x+4) equation: 



3(x+2)=2-(x+4)

We move all terms to the left:

3(x+2)-(2-(x+4))=0

We multiply parentheses

3x-(2-(x+4))+6=0



We calculate terms in parentheses: -(2-(x+4)), so:

2-(x+4)

determiningTheFunctionDomain
-(x+4)+2

We get rid of parentheses

-x-4+2

We add all the numbers together, and all the variables

-1x-2

Back to the equation:

-(-1x-2)



We get rid of parentheses

3x+1x+2+6=0

We add all the numbers together, and all the variables

4x+8=0

We move all terms containing x to the left, all other terms to the right

4x=-8

x=-8/4

x=-2

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