3(x+2)=21(20-3)=11

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Solution for 3(x+2)=21(20-3)=11 equation: 



3(x+2)=21(20-3)=11

We move all terms to the left:

3(x+2)-(21(20-3))=0

We add all the numbers together, and all the variables

3(x+2)-(2117)=0

We add all the numbers together, and all the variables

3(x+2)-2117=0

We multiply parentheses

3x+6-2117=0

We add all the numbers together, and all the variables

3x-2111=0

We move all terms containing x to the left, all other terms to the right

3x=2111

x=2111/3

x=703+2/3

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