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3(x+2)=2x+5(x+2)
We move all terms to the left:
3(x+2)-(2x+5(x+2))=0
We multiply parentheses
3x-(2x+5(x+2))+6=0
We calculate terms in parentheses: -(2x+5(x+2)), so:We get rid of parentheses
2x+5(x+2)
We multiply parentheses
2x+5x+10
We add all the numbers together, and all the variables
7x+10
Back to the equation:
-(7x+10)
3x-7x-10+6=0
We add all the numbers together, and all the variables
-4x-4=0
We move all terms containing x to the left, all other terms to the right
-4x=4
x=4/-4
x=-1
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