3(x+2)=3(2-x)

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Solution for 3(x+2)=3(2-x) equation: 



3(x+2)=3(2-x)

We move all terms to the left:

3(x+2)-(3(2-x))=0

We add all the numbers together, and all the variables

3(x+2)-(3(-1x+2))=0

We multiply parentheses

3x-(3(-1x+2))+6=0



We calculate terms in parentheses: -(3(-1x+2)), so:

3(-1x+2)

We multiply parentheses

-3x+6

Back to the equation:

-(-3x+6)



We get rid of parentheses

3x+3x-6+6=0

We add all the numbers together, and all the variables

6x=0

x=0/6

x=0

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