3(x+2)=3+2(x+1)

Solution for 3(x+2)=3+2(x+1) equation:

3(x+2)=3+2(x+1)

We move all terms to the left:

3(x+2)-(3+2(x+1))=0

We multiply parentheses

3x-(3+2(x+1))+6=0


We calculate terms in parentheses: -(3+2(x+1)), so:

3+2(x+1)

determiningTheFunctionDomain
2(x+1)+3

We multiply parentheses

2x+2+3

We add all the numbers together, and all the variables

2x+5

Back to the equation:

-(2x+5)


We get rid of parentheses

3x-2x-5+6=0

We add all the numbers together, and all the variables

x+1=0

We move all terms containing x to the left, all other terms to the right

x=-1