3(x+2)=30+2(x-4)

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Solution for 3(x+2)=30+2(x-4) equation: 



3(x+2)=30+2(x-4)

We move all terms to the left:

3(x+2)-(30+2(x-4))=0

We multiply parentheses

3x-(30+2(x-4))+6=0



We calculate terms in parentheses: -(30+2(x-4)), so:

30+2(x-4)

determiningTheFunctionDomain
2(x-4)+30

We multiply parentheses

2x-8+30

We add all the numbers together, and all the variables

2x+22

Back to the equation:

-(2x+22)



We get rid of parentheses

3x-2x-22+6=0

We add all the numbers together, and all the variables

x-16=0

We move all terms containing x to the left, all other terms to the right

x=16

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