3(x+2)=3x+43(x+2)=3x+4

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Solution for 3(x+2)=3x+43(x+2)=3x+4 equation: 



3(x+2)=3x+43(x+2)=3x+4

We move all terms to the left:

3(x+2)-(3x+43(x+2))=0

We multiply parentheses

3x-(3x+43(x+2))+6=0



We calculate terms in parentheses: -(3x+43(x+2)), so:

3x+43(x+2)

We multiply parentheses

3x+43x+86

We add all the numbers together, and all the variables

46x+86

Back to the equation:

-(46x+86)



We get rid of parentheses

3x-46x-86+6=0

We add all the numbers together, and all the variables

-43x-80=0

We move all terms containing x to the left, all other terms to the right

-43x=80

x=80/-43

x=-1+37/43

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