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3(x+2)=3x-27-(x-9)
We move all terms to the left:
3(x+2)-(3x-27-(x-9))=0
We multiply parentheses
3x-(3x-27-(x-9))+6=0
We calculate terms in parentheses: -(3x-27-(x-9)), so:We get rid of parentheses
3x-27-(x-9)
determiningTheFunctionDomain 3x-(x-9)-27
We get rid of parentheses
3x-x+9-27
We add all the numbers together, and all the variables
2x-18
Back to the equation:
-(2x-18)
3x-2x+18+6=0
We add all the numbers together, and all the variables
x+24=0
We move all terms containing x to the left, all other terms to the right
x=-24
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