3(x+2)=4(6+2x)

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Solution for 3(x+2)=4(6+2x) equation: 



3(x+2)=4(6+2x)

We move all terms to the left:

3(x+2)-(4(6+2x))=0

We add all the numbers together, and all the variables

3(x+2)-(4(2x+6))=0

We multiply parentheses

3x-(4(2x+6))+6=0



We calculate terms in parentheses: -(4(2x+6)), so:

4(2x+6)

We multiply parentheses

8x+24

Back to the equation:

-(8x+24)



We get rid of parentheses

3x-8x-24+6=0

We add all the numbers together, and all the variables

-5x-18=0

We move all terms containing x to the left, all other terms to the right

-5x=18

x=18/-5

x=-3+3/5

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