3(x+2)=6(x+12)

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Solution for 3(x+2)=6(x+12) equation: 



3(x+2)=6(x+12)

We move all terms to the left:

3(x+2)-(6(x+12))=0

We multiply parentheses

3x-(6(x+12))+6=0



We calculate terms in parentheses: -(6(x+12)), so:

6(x+12)

We multiply parentheses

6x+72

Back to the equation:

-(6x+72)



We get rid of parentheses

3x-6x-72+6=0

We add all the numbers together, and all the variables

-3x-66=0

We move all terms containing x to the left, all other terms to the right

-3x=66

x=66/-3

x=-22

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