3(x+2)=6(x-1)+3

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Solution for 3(x+2)=6(x-1)+3 equation: 



3(x+2)=6(x-1)+3

We move all terms to the left:

3(x+2)-(6(x-1)+3)=0

We multiply parentheses

3x-(6(x-1)+3)+6=0



We calculate terms in parentheses: -(6(x-1)+3), so:

6(x-1)+3

We multiply parentheses

6x-6+3

We add all the numbers together, and all the variables

6x-3

Back to the equation:

-(6x-3)



We get rid of parentheses

3x-6x+3+6=0

We add all the numbers together, and all the variables

-3x+9=0

We move all terms containing x to the left, all other terms to the right

-3x=-9

x=-9/-3

x=+3

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