3(x+2)=6x+12+6

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Solution for 3(x+2)=6x+12+6 equation: 



3(x+2)=6x+12+6

We move all terms to the left:

3(x+2)-(6x+12+6)=0

We add all the numbers together, and all the variables

3(x+2)-(6x+18)=0

We multiply parentheses

3x-(6x+18)+6=0

We get rid of parentheses

3x-6x-18+6=0

We add all the numbers together, and all the variables

-3x-12=0

We move all terms containing x to the left, all other terms to the right

-3x=12

x=12/-3

x=-4

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