3(x+2)=7(9x-6)+10

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Solution for 3(x+2)=7(9x-6)+10 equation: 



3(x+2)=7(9x-6)+10

We move all terms to the left:

3(x+2)-(7(9x-6)+10)=0

We multiply parentheses

3x-(7(9x-6)+10)+6=0



We calculate terms in parentheses: -(7(9x-6)+10), so:

7(9x-6)+10

We multiply parentheses

63x-42+10

We add all the numbers together, and all the variables

63x-32

Back to the equation:

-(63x-32)



We get rid of parentheses

3x-63x+32+6=0

We add all the numbers together, and all the variables

-60x+38=0

We move all terms containing x to the left, all other terms to the right

-60x=-38

x=-38/-60

x=19/30

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