3(x+2)=7(x+1)

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Solution for 3(x+2)=7(x+1) equation: 



3(x+2)=7(x+1)

We move all terms to the left:

3(x+2)-(7(x+1))=0

We multiply parentheses

3x-(7(x+1))+6=0



We calculate terms in parentheses: -(7(x+1)), so:

7(x+1)

We multiply parentheses

7x+7

Back to the equation:

-(7x+7)



We get rid of parentheses

3x-7x-7+6=0

We add all the numbers together, and all the variables

-4x-1=0

We move all terms containing x to the left, all other terms to the right

-4x=1

x=1/-4

x=-1/4

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