3(x+2)=72+x

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Solution for 3(x+2)=72+x equation: 



3(x+2)=72+x

We move all terms to the left:

3(x+2)-(72+x)=0

We add all the numbers together, and all the variables

3(x+2)-(x+72)=0

We multiply parentheses

3x-(x+72)+6=0

We get rid of parentheses

3x-x-72+6=0

We add all the numbers together, and all the variables

2x-66=0

We move all terms containing x to the left, all other terms to the right

2x=66

x=66/2

x=33

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