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3(x+2)=9(x-3)
We move all terms to the left:
3(x+2)-(9(x-3))=0
We multiply parentheses
3x-(9(x-3))+6=0
We calculate terms in parentheses: -(9(x-3)), so:We get rid of parentheses
9(x-3)
We multiply parentheses
9x-27
Back to the equation:
-(9x-27)
3x-9x+27+6=0
We add all the numbers together, and all the variables
-6x+33=0
We move all terms containing x to the left, all other terms to the right
-6x=-33
x=-33/-6
x=5+1/2
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