3(x+2)=x+x+12

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Solution for 3(x+2)=x+x+12 equation: 



3(x+2)=x+x+12

We move all terms to the left:

3(x+2)-(x+x+12)=0

We add all the numbers together, and all the variables

3(x+2)-(2x+12)=0

We multiply parentheses

3x-(2x+12)+6=0

We get rid of parentheses

3x-2x-12+6=0

We add all the numbers together, and all the variables

x-6=0

We move all terms containing x to the left, all other terms to the right

x=6

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