3(x+2-7)=(x-4)+9

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Solution for 3(x+2-7)=(x-4)+9 equation: 



3(x+2-7)=(x-4)+9

We move all terms to the left:

3(x+2-7)-((x-4)+9)=0

We add all the numbers together, and all the variables

3(x-5)-((x-4)+9)=0

We multiply parentheses

3x-((x-4)+9)-15=0



We calculate terms in parentheses: -((x-4)+9), so:

(x-4)+9

We get rid of parentheses

x-4+9

We add all the numbers together, and all the variables

x+5

Back to the equation:

-(x+5)



We get rid of parentheses

3x-x-5-15=0

We add all the numbers together, and all the variables

2x-20=0

We move all terms containing x to the left, all other terms to the right

2x=20

x=20/2

x=10

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