3(x+20)=8+2(x-2)

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Solution for 3(x+20)=8+2(x-2) equation: 



3(x+20)=8+2(x-2)

We move all terms to the left:

3(x+20)-(8+2(x-2))=0

We multiply parentheses

3x-(8+2(x-2))+60=0



We calculate terms in parentheses: -(8+2(x-2)), so:

8+2(x-2)

determiningTheFunctionDomain
2(x-2)+8

We multiply parentheses

2x-4+8

We add all the numbers together, and all the variables

2x+4

Back to the equation:

-(2x+4)



We get rid of parentheses

3x-2x-4+60=0

We add all the numbers together, and all the variables

x+56=0

We move all terms containing x to the left, all other terms to the right

x=-56

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