3(x+21)+6x=10-2(x+4)

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Solution for 3(x+21)+6x=10-2(x+4) equation: 



3(x+21)+6x=10-2(x+4)

We move all terms to the left:

3(x+21)+6x-(10-2(x+4))=0

We add all the numbers together, and all the variables

6x+3(x+21)-(10-2(x+4))=0

We multiply parentheses

6x+3x-(10-2(x+4))+63=0



We calculate terms in parentheses: -(10-2(x+4)), so:

10-2(x+4)

determiningTheFunctionDomain
-2(x+4)+10

We multiply parentheses

-2x-8+10

We add all the numbers together, and all the variables

-2x+2

Back to the equation:

-(-2x+2)



We add all the numbers together, and all the variables

9x-(-2x+2)+63=0

We get rid of parentheses

9x+2x-2+63=0

We add all the numbers together, and all the variables

11x+61=0

We move all terms containing x to the left, all other terms to the right

11x=-61

x=-61/11

x=-5+6/11

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