3(x+3)(x+3)-4=30

Solution for 3(x+3)(x+3)-4=30 equation:

3(x+3)(x+3)-4=30

We move all terms to the left:

3(x+3)(x+3)-4-(30)=0

We add all the numbers together, and all the variables

3(x+3)(x+3)-34=0

We multiply parentheses ..

3(+x^2+3x+3x+9)-34=0

We multiply parentheses

3x^2+9x+9x+27-34=0

We add all the numbers together, and all the variables

3x^2+18x-7=0

a = 3; b = 18; c = -7;
Δ = b2-4ac
Δ = 182-4·3·(-7)
Δ = 408
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{408}=\sqrt{4*102}=\sqrt{4}*\sqrt{102}=2\sqrt{102}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-2\sqrt{102}}{2*3}=\frac{-18-2\sqrt{102}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+2\sqrt{102}}{2*3}=\frac{-18+2\sqrt{102}}{6}
$