3(x+3)(x-2)=0

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Solution for 3(x+3)(x-2)=0 equation:



3(x+3)(x-2)=0
We multiply parentheses ..
3(+x^2-2x+3x-6)=0
We multiply parentheses
3x^2-6x+9x-18=0
We add all the numbers together, and all the variables
3x^2+3x-18=0
a = 3; b = 3; c = -18;
Δ = b2-4ac
Δ = 32-4·3·(-18)
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{225}=15$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-15}{2*3}=\frac{-18}{6} =-3 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+15}{2*3}=\frac{12}{6} =2 $

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