3(x+3)+1=2(x-6)

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Solution for 3(x+3)+1=2(x-6) equation: 



3(x+3)+1=2(x-6)

We move all terms to the left:

3(x+3)+1-(2(x-6))=0

We multiply parentheses

3x-(2(x-6))+9+1=0



We calculate terms in parentheses: -(2(x-6)), so:

2(x-6)

We multiply parentheses

2x-12

Back to the equation:

-(2x-12)



We add all the numbers together, and all the variables

3x-(2x-12)+10=0

We get rid of parentheses

3x-2x+12+10=0

We add all the numbers together, and all the variables

x+22=0

We move all terms containing x to the left, all other terms to the right

x=-22

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