3(x+3)+2(2x-4)=12(2x-1)

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Solution for 3(x+3)+2(2x-4)=12(2x-1) equation:



3(x+3)+2(2x-4)=12(2x-1)
We move all terms to the left:
3(x+3)+2(2x-4)-(12(2x-1))=0
We multiply parentheses
3x+4x-(12(2x-1))+9-8=0
We calculate terms in parentheses: -(12(2x-1)), so:
12(2x-1)
We multiply parentheses
24x-12
Back to the equation:
-(24x-12)
We add all the numbers together, and all the variables
7x-(24x-12)+1=0
We get rid of parentheses
7x-24x+12+1=0
We add all the numbers together, and all the variables
-17x+13=0
We move all terms containing x to the left, all other terms to the right
-17x=-13
x=-13/-17
x=13/17

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