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3(x+3)+3(x+1)=-12
We move all terms to the left:
3(x+3)+3(x+1)-(-12)=0
We add all the numbers together, and all the variables
3(x+3)+3(x+1)+12=0
We multiply parentheses
3x+3x+9+3+12=0
We add all the numbers together, and all the variables
6x+24=0
We move all terms containing x to the left, all other terms to the right
6x=-24
x=-24/6
x=-4
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