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3(x+3)+3=2(x+6)
We move all terms to the left:
3(x+3)+3-(2(x+6))=0
We multiply parentheses
3x-(2(x+6))+9+3=0
We calculate terms in parentheses: -(2(x+6)), so:We add all the numbers together, and all the variables
2(x+6)
We multiply parentheses
2x+12
Back to the equation:
-(2x+12)
3x-(2x+12)+12=0
We get rid of parentheses
3x-2x-12+12=0
We add all the numbers together, and all the variables
x=0
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