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3(x+3)+4=5x-2(-5+x)
We move all terms to the left:
3(x+3)+4-(5x-2(-5+x))=0
We add all the numbers together, and all the variables
3(x+3)-(5x-2(x-5))+4=0
We multiply parentheses
3x-(5x-2(x-5))+9+4=0
We calculate terms in parentheses: -(5x-2(x-5)), so:We add all the numbers together, and all the variables
5x-2(x-5)
We multiply parentheses
5x-2x+10
We add all the numbers together, and all the variables
3x+10
Back to the equation:
-(3x+10)
3x-(3x+10)+13=0
We get rid of parentheses
3x-3x-10+13=0
We add all the numbers together, and all the variables
3!=0
There is no solution for this equation
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