3(x+3)+4x-5=7(x+1)-6

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Solution for 3(x+3)+4x-5=7(x+1)-6 equation:


Simplifying
3(x + 3) + 4x + -5 = 7(x + 1) + -6

Reorder the terms:
3(3 + x) + 4x + -5 = 7(x + 1) + -6
(3 * 3 + x * 3) + 4x + -5 = 7(x + 1) + -6
(9 + 3x) + 4x + -5 = 7(x + 1) + -6

Reorder the terms:
9 + -5 + 3x + 4x = 7(x + 1) + -6

Combine like terms: 9 + -5 = 4
4 + 3x + 4x = 7(x + 1) + -6

Combine like terms: 3x + 4x = 7x
4 + 7x = 7(x + 1) + -6

Reorder the terms:
4 + 7x = 7(1 + x) + -6
4 + 7x = (1 * 7 + x * 7) + -6
4 + 7x = (7 + 7x) + -6

Reorder the terms:
4 + 7x = 7 + -6 + 7x

Combine like terms: 7 + -6 = 1
4 + 7x = 1 + 7x

Add '-7x' to each side of the equation.
4 + 7x + -7x = 1 + 7x + -7x

Combine like terms: 7x + -7x = 0
4 + 0 = 1 + 7x + -7x
4 = 1 + 7x + -7x

Combine like terms: 7x + -7x = 0
4 = 1 + 0
4 = 1

Solving
4 = 1

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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