3(x+3)+x=1+2(x+12)

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Solution for 3(x+3)+x=1+2(x+12) equation: 



3(x+3)+x=1+2(x+12)

We move all terms to the left:

3(x+3)+x-(1+2(x+12))=0

We add all the numbers together, and all the variables

x+3(x+3)-(1+2(x+12))=0

We multiply parentheses

x+3x-(1+2(x+12))+9=0



We calculate terms in parentheses: -(1+2(x+12)), so:

1+2(x+12)

determiningTheFunctionDomain
2(x+12)+1

We multiply parentheses

2x+24+1

We add all the numbers together, and all the variables

2x+25

Back to the equation:

-(2x+25)



We add all the numbers together, and all the variables

4x-(2x+25)+9=0

We get rid of parentheses

4x-2x-25+9=0

We add all the numbers together, and all the variables

2x-16=0

We move all terms containing x to the left, all other terms to the right

2x=16

x=16/2

x=8

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