3(x+3)+x=2(x+1)+3

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Solution for 3(x+3)+x=2(x+1)+3 equation: 



3(x+3)+x=2(x+1)+3

We move all terms to the left:

3(x+3)+x-(2(x+1)+3)=0

We add all the numbers together, and all the variables

x+3(x+3)-(2(x+1)+3)=0

We multiply parentheses

x+3x-(2(x+1)+3)+9=0



We calculate terms in parentheses: -(2(x+1)+3), so:

2(x+1)+3

We multiply parentheses

2x+2+3

We add all the numbers together, and all the variables

2x+5

Back to the equation:

-(2x+5)



We add all the numbers together, and all the variables

4x-(2x+5)+9=0

We get rid of parentheses

4x-2x-5+9=0

We add all the numbers together, and all the variables

2x+4=0

We move all terms containing x to the left, all other terms to the right

2x=-4

x=-4/2

x=-2

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