3(x+3)+x=2(x-1)=3

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Solution for 3(x+3)+x=2(x-1)=3 equation: 



3(x+3)+x=2(x-1)=3

We move all terms to the left:

3(x+3)+x-(2(x-1))=0

We add all the numbers together, and all the variables

x+3(x+3)-(2(x-1))=0

We multiply parentheses

x+3x-(2(x-1))+9=0



We calculate terms in parentheses: -(2(x-1)), so:

2(x-1)

We multiply parentheses

2x-2

Back to the equation:

-(2x-2)



We add all the numbers together, and all the variables

4x-(2x-2)+9=0

We get rid of parentheses

4x-2x+2+9=0

We add all the numbers together, and all the variables

2x+11=0

We move all terms containing x to the left, all other terms to the right

2x=-11

x=-11/2

x=-5+1/2

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