3(x+3)-(2x+4)=4(4x+2)+27

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Solution for 3(x+3)-(2x+4)=4(4x+2)+27 equation: 



3(x+3)-(2x+4)=4(4x+2)+27

We move all terms to the left:

3(x+3)-(2x+4)-(4(4x+2)+27)=0

We multiply parentheses

3x-(2x+4)-(4(4x+2)+27)+9=0

We get rid of parentheses

3x-2x-(4(4x+2)+27)-4+9=0



We calculate terms in parentheses: -(4(4x+2)+27), so:

4(4x+2)+27

We multiply parentheses

16x+8+27

We add all the numbers together, and all the variables

16x+35

Back to the equation:

-(16x+35)



We add all the numbers together, and all the variables

x-(16x+35)+5=0

We get rid of parentheses

x-16x-35+5=0

We add all the numbers together, and all the variables

-15x-30=0

We move all terms containing x to the left, all other terms to the right

-15x=30

x=30/-15

x=-2

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