3(x+3)-2(x+1)=2(x-1)+4x

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Solution for 3(x+3)-2(x+1)=2(x-1)+4x equation: 



3(x+3)-2(x+1)=2(x-1)+4x

We move all terms to the left:

3(x+3)-2(x+1)-(2(x-1)+4x)=0

We multiply parentheses

3x-2x-(2(x-1)+4x)+9-2=0



We calculate terms in parentheses: -(2(x-1)+4x), so:

2(x-1)+4x

We add all the numbers together, and all the variables

4x+2(x-1)

We multiply parentheses

4x+2x-2

We add all the numbers together, and all the variables

6x-2

Back to the equation:

-(6x-2)



We add all the numbers together, and all the variables

x-(6x-2)+7=0

We get rid of parentheses

x-6x+2+7=0

We add all the numbers together, and all the variables

-5x+9=0

We move all terms containing x to the left, all other terms to the right

-5x=-9

x=-9/-5

x=1+4/5

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