3(x+3)-3=3(2x+1)

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Solution for 3(x+3)-3=3(2x+1) equation: 



3(x+3)-3=3(2x+1)

We move all terms to the left:

3(x+3)-3-(3(2x+1))=0

We multiply parentheses

3x-(3(2x+1))+9-3=0



We calculate terms in parentheses: -(3(2x+1)), so:

3(2x+1)

We multiply parentheses

6x+3

Back to the equation:

-(6x+3)



We add all the numbers together, and all the variables

3x-(6x+3)+6=0

We get rid of parentheses

3x-6x-3+6=0

We add all the numbers together, and all the variables

-3x+3=0

We move all terms containing x to the left, all other terms to the right

-3x=-3

x=-3/-3

x=1

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