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3(x+3)-4=3(x-4)
We move all terms to the left:
3(x+3)-4-(3(x-4))=0
We multiply parentheses
3x-(3(x-4))+9-4=0
We calculate terms in parentheses: -(3(x-4)), so:We add all the numbers together, and all the variables
3(x-4)
We multiply parentheses
3x-12
Back to the equation:
-(3x-12)
3x-(3x-12)+5=0
We get rid of parentheses
3x-3x+12+5=0
We add all the numbers together, and all the variables
17!=0
There is no solution for this equation
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