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3(x+3)-5(2x+4)+6(4x-3)=3(6x+1)-3(6x-5)-13
We move all terms to the left:
3(x+3)-5(2x+4)+6(4x-3)-(3(6x+1)-3(6x-5)-13)=0
We multiply parentheses
3x-10x+24x-(3(6x+1)-3(6x-5)-13)+9-20-18=0
We calculate terms in parentheses: -(3(6x+1)-3(6x-5)-13), so:We add all the numbers together, and all the variables
3(6x+1)-3(6x-5)-13
We multiply parentheses
18x-18x+3+15-13
We add all the numbers together, and all the variables
5
Back to the equation:
-(5)
17x-34=0
We move all terms containing x to the left, all other terms to the right
17x=34
x=34/17
x=2
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