3(x+3)-5=16+x

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Solution for 3(x+3)-5=16+x equation: 



3(x+3)-5=16+x

We move all terms to the left:

3(x+3)-5-(16+x)=0

We add all the numbers together, and all the variables

3(x+3)-(x+16)-5=0

We multiply parentheses

3x-(x+16)+9-5=0

We get rid of parentheses

3x-x-16+9-5=0

We add all the numbers together, and all the variables

2x-12=0

We move all terms containing x to the left, all other terms to the right

2x=12

x=12/2

x=6

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