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3(x+3)-5=3(x-2)
We move all terms to the left:
3(x+3)-5-(3(x-2))=0
We multiply parentheses
3x-(3(x-2))+9-5=0
We calculate terms in parentheses: -(3(x-2)), so:We add all the numbers together, and all the variables
3(x-2)
We multiply parentheses
3x-6
Back to the equation:
-(3x-6)
3x-(3x-6)+4=0
We get rid of parentheses
3x-3x+6+4=0
We add all the numbers together, and all the variables
10!=0
There is no solution for this equation
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