3(x+3)-5=7x+20

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Solution for 3(x+3)-5=7x+20 equation: 



3(x+3)-5=7x+20

We move all terms to the left:

3(x+3)-5-(7x+20)=0

We multiply parentheses

3x-(7x+20)+9-5=0

We get rid of parentheses

3x-7x-20+9-5=0

We add all the numbers together, and all the variables

-4x-16=0

We move all terms containing x to the left, all other terms to the right

-4x=16

x=16/-4

x=-4

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