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3(x+3)-9=5(x+2)
We move all terms to the left:
3(x+3)-9-(5(x+2))=0
We multiply parentheses
3x-(5(x+2))+9-9=0
We calculate terms in parentheses: -(5(x+2)), so:We add all the numbers together, and all the variables
5(x+2)
We multiply parentheses
5x+10
Back to the equation:
-(5x+10)
3x-(5x+10)=0
We get rid of parentheses
3x-5x-10=0
We add all the numbers together, and all the variables
-2x-10=0
We move all terms containing x to the left, all other terms to the right
-2x=10
x=10/-2
x=-5
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